C Program to find the number of elements in an array

Arushi Dwivedi | March 25, 2021 | C Programming Example | No Comments

In this C Programming example, we will implement the program to find the number of elements in an array and print the output on the console.

Table of Contents

1. Number of elements in an array

To get the number of elements in an array we can calculate the length of an array by using the sizeof operator which gives the size of an object or a type in bytes. So, to calculate the elements in the array we just divide the number of allocated bytes by the number of bytes of the array’s data type using sizeof().

Example

Input: arr[]={1, 2, 3, 4, 5, 6, 7}
Output: The number of elemnts present in the array are: 7

Helpful topics to understand this program better are-

2. C Program to find number of elements in an array

Let’s discuss the pseudocode for the program to find the number of elements in an array in C.

We will use sizeof() method to find the size of the whole array and divide it by the size of the array’s first element.

Pseudocode
Start
  Intialize arr[]
  # length_array = size of whole array / size of first item
  length_array = sizeof(arr) / sizeof(arr[0])
End

Let us now implement the above execution of the program to find the number of elements in an array in C.

#include <stdio.h>
int main() {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int arrayLength = sizeof(arr) / sizeof(arr[0]);

  printf("Number of elements present in the given array is: %d", arrayLength);
  return 0;
}

Output
Number of elements present in the given array is: 10

3. Conclusion

In this C Programming example, we have discussed how to find the number of elements in an array using the sizeof operator.

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